Modulation index of an amplitude modulated wave is 50% and power dissipated in transmission 18 kW. What is the rate of energy dissipation for each side band?

Explanation

Modulation index, `beta = 50% = (1)/(2)`
We know, `P_(AM) = P_(C)(1 + (beta^(2))/(2)) " " or, 18 = P_(C) [ 1 + (((1)/(2))^(2))/(2)] = (9)/(8) P_(C)`
i.e, Power of carrier wave,
` P_(C) = 18 xx (8)/(9) = 16 `kW
Increase in power, due to modulation = 18 - 16 = 2 kW.
This power is distributed equally in the two sidebands.
`therefore` Rate of energy dissipation for each sideband
` = (2)/(2) = 1 ` kW