When `._(88)^(226)Ra` emits an `alpha`-particle, the new element formed belongs to:

""_(88)^(226)Ra emits an o-particle and the daughter element is:

._(92)^(235)U belongs to IIIB group of the periodic table, It loses one alpha- particle, the new element will belong to the group.

An element group-III with atomic number 92 and mass number 238 undergoes decay of one alpha particle. The newely formed element belongs to

""_(92)U^(235) belong to group IIIB to periodic table. If it loses one alpha particle, the new element will belong to the group

When Be is bombarded with alpha -particles, a grew element viz carbon is formed whereas, when gold is bombarded with alpha -particles, no new elements are formed. Explain.

An heavier elements continuosly emits alpha - and beta -particles. The finally stable element may belong to :