Suppose ideal gas equation follows `VP^(3) = contant`. Initial temperature and volume of the gas are T and V respectively. If gas expand to `27V` temperature will become

An ideal gas is found to obey a gas law, Vp^2 = constant .Initial temperature and volume of the gas are T and V respectively. IF the gas expands to a volume 2V, what will be the effect on temperature?

A gas is found to obey the law P^(2) V= constant the innitial temperature and volume are T_(0) and V_(0) . If the gas expands to volume 2V_(0) , its final temperature becomes-

A gas is found to obey the law P^(2)V = constant . The initial temperature and volume are T_(0) and V_(0) . If the gas expands to a volume 3 V_(0) , its final temperature becomes

A gas is found to obey the law P^(2)V = constant . The initial temperature and volume are T_(0) and V_(0) . If the gas expands to a volume 3 V_(0) , its final temperature becomes

A gas is found to obey the law p^(2) V = constant. The initial temperature and volume are T_(0) and V_(0) . If the gas expands to a volume 3V_(0) , its final temperature becomes

A gas is found to be obeyed the law p^2V = constant . The initial temperature and volume are T_0 and V_0 . If the gas expands to a volume 3 V_0 , then the final temperature becomes.

A gas is found to be obeyed the law p^2V = constant . The initial temperature and volume are T_0 and V_0 . If the gas expands to a volume 3 V_0 , then the final temperature becomes.