A mole of steam is condensed at `100^(@)` C, the water is cooled to `0^(@)`C and frozen to i.e . What is the difference in entropies of the stem and ice? The heat of vaporization and fusion are `540 cal" "gm^(-1)` and `80 cal" "gm ^(-1)` respectively . Use the average heat capacity of liquild water as `1 cal" "gm^(-1)` `degree^(-1)`.

A mole of steam is condensed at 100^(@) C, the water is cooled to 0^(@) C and frozen to ice . What is the difference in entropies of the steam and ice? The heat of vaporization and fusion are 540 cal" "gm^(-1) and 80 cal" "gm ^(-1) respectively . Use the average heat capacity of liquild water as 1 cal" "gm^(-1) degree^(-1) . a. Entropy change during the condensation of steam is -26.06 cal//^(@)C b. Entropy change during cooling of water from 100^(@)C "to" 0^(@)C "is" - 5.62 cal//^(@)C c. Entropy change during freezing of water at 0^(@)C "is" -5.27 cal//^(@)C d. Total entropy changwe is -36.95 cal//^(@)C

One mole of ice is melted at 0^(@)C and then is heated to 100^(@)C . What is the difference in entropies of the steam and ice? The heats of vaporisation and fusion are 540 cal g^(-1) and 80 cal g^(-1) respectively. Use the average heat capacity of liquid water as 1cal g^(-1) degree^(-1)

If x gm of steam at 100^(@) C is mixed with 5x gm of ice at 0^(@)C , calculate the final temperature of resultiong mixture. The heat of vapourisation and fusion are 540 cal gm^(-1) and 80 cal gm^(-1) respectively.

If x gm of steam at 100^(@) C is mixed with 5x gm of ice at 0^(@)C , calculate the final temperature of resultiong mixture. The heat of vapourisation and fusion are 540 cal gm^(-1) and 80 cal gm^(-1) respectively.

How much heat is required to change 10g ice at 0^(@)C to steam at 100^(@)C ? Latent heat of fusion and vaporisation for H_(2)O are 80 cl g^(-1) and 540 cal g^(-1) , respectively. Specific heat of water is 1cal g^(-1) .

How much heat is required to change 10g ice at 10^(@)C to steam at 100^(@)C ? Latent heat of fusion and vaporisation for H_(2)O are 80 cl g^(-1) and 540 cal g^(-1) , respectively. Specific heat of water is 1cal g^(-1) .

How much heat is required to change 10g ice at 10^(@)C to steam at 100^(@)C ? Latent heat of fusion and vaporisation for H_(2)O are 80 cl g^(-1) and 540 cal g^(-1) , respectively. Specific heat of water is 1cal g^(-1) .

Steam at 100°C is passed into 100 g of ice at 0°C . Finally when 80g ice melts the mass of water present will be [Latent heat of fusion and vaporization are 80 cal g^(-1) and 540 cal g^(-1) respectively, specific heat of water = 1 cal g^(-1) °C^(-1) ]

Steam at 100°C is passed into 100 g of ice at 0°C . Finally when 80g ice melts the mass of water present will be [Latent heat of fusion and vaporazisation are 80 cal g^(-1) and 540 cal g^(-1) respectively, specific heat of water = 1 cal g^(-1) °C^(-1) ]

How much heat is required to change 5 gram ice (0^@C) to steam at 100^@C ? Latent heat of fusion and vaporization for water are 80 cal/g and 540 cal/g respectively . Specific heat of water is 1 cal/ g/k.