In the given figure, ABCD is a square and `anglePQR=90^(@).If PB=QC=DR,` prove that.
(i) QB = RC
(ii) PQ = QR
(iii) `angleQPR=45^(@)`

In the fig. ABCD is a square and anglePQR=90^@ PB=QC=DR, prove that:QB=RC

In the fig. ABCD is a square and anglePQR=90^@ PB=QC=DR, prove that:PQ=QR

In the fig. ABCD is a square and anglePQR=90^@ PB=QC=DR, prove that: angleQPR=45^@

In the given figure , DEFG is a square and angleBAC= 90^(@) prove that (i) triangleAGF~ triangleDBG (ii) triangleAGF~triangleEFC

In the given figure, angleSPR=angleQRP and angleRSP=anglePQR . Prove that : (i) PQ=RS (ii) PS=QR

In the figure , M is the midpoint of QR . angle PRQ = 90^(@) . Prove that , PQ^(2) = 4PM^(2) - 3PR^(2) .

In the given figure, ABCD is a quadrilateral in which AD = BC and angleDAB=angleCBA. Prove that (i) DeltaABD~=DeltaBAC, (ii) BD = AC, (iii) angleABD=angleBAC.