Two moles of helium are mixed with n moles of hydrogen. If `(Cp)/(Cv)=(3)/(2)` for the mixture, then the value of n is :

Two mole of argon are mixed with one mole of hydrogen, then C_p/C_V for the mixture is nearly

Two moles of helium (He) are mixed with four moles of hydrogen (H_2) . Find (a) (C_(V) of the mixture (b) (C_(P) of the mixture and ( c) (gamma) of the mixture.

Two moles of helium (He) are mixed with four moles of hydrogen (H_2) . Find (a) (C_(V) of the mixture (b) (C_(P) of the mixture and ( c) (gamma) of the mixture.

Two moles of helium are mixed with n moles of hydrogen. The root mean spure (rms) speed of the gas molecules in the mexture is sqrt2 times the speed of sound in the mixture. Then value of n is

Two moles of helium are mixed with n moles of hydrogen. The root mean spure (rms) speed of the gas molecules in the mexture is sqrt2 times the speed of sound in the mixture. Then value of n is

Five moles of helium are mixed with two moles of hydrogen to form a mixture. Take molar mass of helium M_(1) = 4g and that of hydrogen M_(2) = 2g The equivalent degree of freedom f of the mixture is

Five moles of helium are mixed with two moles of hydrogen to form a mixture. Take molar mass of helium M_(1) = 4g and that of hydrogen M_(2) = 2g The equivalent molar mass of the mixture is

Five moles of helium are mixed with two moles of hydrogen to form a mixture. Take molar mass of helium M_(1) = 4g and that of hydrogen M_(2) = 2g The equivalent degree of freedom f of the mixture is

Five moles of helium are mixed with two moles of hydrogen to form a mixture. Take molar mass of helium M_(1) = 4g and that of hydrogen M_(2) = 2g The equivalent molar mass of the mixture is

Five moles of helium are mixed with two moles of hydrogen to form a mixture. Take molar mass of helium M_(1) = 4g and that of hydrogen M_(2) = 2g The equivalent molar mass of the mixture is