Two particles A and B have de-Broglie's wavelength `30Å` combined to from a single particle. C Momentum is conserved in this processs. The possible de-Broglile's wavelength of C is (the motion in one dimensional)

Two particles A and B of de-broglie wavelength lambda_(1) and lambda_(2) combine to from a particle C. The process conserves momentum. Find the de-Broglie wavelength of the particle C. (The motion is one dimensional).

Two particles A and B of de-broglie wavelength lambda_(1) and lambda_(2) combine to from a particle C. The process conserves momentum. Find the de-Broglie wavelength of the particle C. (The motion is one dimensional).

Two particles A and B of de-broglie wavelength lambda_(1) and lambda_(2) combine to from a particle C. The process conserves momentum. Find the de-Broglie wavelength of the particle C. (The motion is one dimensional).

Two particles A and B of de-Broglie wavelength lambda_(1) and lambda_(2) combine to form a particle C.The process conserves momentum .Find the de-Broglie wavelength of the particle C.(The motion is one -dimensional).

The de-Broglie wavelength (lambda) of a material particle of momentum (p) is given by

For particles having same K.E., the de-Broglie wavelength is

For particles having same K.E., the de-Broglie wavelength is

The de Broglie wavelength lambda of a particle

The de-Broglie wavelength associated with a particle of momentum p is given as :