`A` lead bullet of `10g` travelling at `300m//s` strikes against a block of wood and comes to rest. Assuming `50%` heat is absorbed by the bullet, the increase in its temperature is (sp-heat of lead is `150J//Kg-K`)

A lead bullet of mass 10 g travelling at 300 m//s strikes against a block of wood and comes to rest. Assuming 50% of heat is absorbed by the bullet, the increase in its temperature is (Specific heat of lead = 150 J//kg^(@)C )

A lead bullet of mass 50g moving with a velocity of 100ms^(-1) strikes a target. If 40% of the heat produced is retained by the bullet, calculate the rise in its temperature. Specific heat of lead = 0.03 cal g^(-1)K^(-1) and J = 4.2 J cal^(-1)

A lead bullet of mass 21 g travelling at a speed of 100m//s comes to rest in a wooden block . If no heat is taken away by the wood , the rise in temperature of the bullet in the wood nearly is (specified heat of lead = 30 cal//kg^(@)C )

A lead ball moving with a velocity v strikes a wall and stops. If 50% of its energy is onverted into heat. The increase in temperature is (Specific heat of lead is S)

A lead ball moving with velocity v strikes a wall and stops. iF 50% of its energy is converted into heat, then what will be the increase in temperature ? Specific heat of lead is s

A lead bullet of mass 21g travelling at a speed of 100 ms^(-1) comes to rest in a wooden block. If no heat is taken away by the wood, the rise in temperature of the bullet in the wood nearly is (Sp. Heat of lead 80cal/kg .^(@)C )

A bullet of mass 0.1Kg moves with velocity 10 m/s it strikes a block and comes to rest after travels 0.5 m inside block. Find retardation of bullet