`lim_(x->oo)(3/x)[x/4]= p/q`find `p+q`

lim_(x rarr oo)((3)/(x))[(x)/(4)]=(p)/(q) find p+q

lim_(x rarr oo)(3)/(x) [(x)/(4)] =(p)/(q) find p and q

lim _(xtooo)3/x [(x)/(4)]=p/q where [.] denotes greatest integer function), then p+q (where p,q are relative prime) is:

lim _(xtooo)3/x [(x)/(4)]=p/q where [.] denotes greatest integer function), then p+q (where p,q are relative prime) is:

Let P and Q be polynomials. Find Lim_(x->oo) (P(x))/(Q(x)) if the degree of P is

The value of lim_(xto0+)(x)/(p)[(q)/(x)] is

Lim_(x to oo) (px+q)/(qx+p)=l and Lim_(x to 0)(px+q)/(qx+p)=m where p,q ne 0 then lm is

The value of lim_(x to1)(p/(1-x^p)-q/(1-x^q)),p ,q , in N , equal (a) (p+q)/2 (b) (p q)/2 (c) (p-q)/2 (d) sqrt(p/q)

The value of lim_(x to1)(p/(1-x^p)-q/(1-x^q)),p ,q , in N , equal (a) (p+q)/2 (b) (p q)/2 (c) (p-q)/2 (d) sqrt(p/q)

Number of integral solution of ((2x-3)^(2))/(16)<=1 is p and for -4<(x^(2))/(x)<=5 is q then find p and q