if `f(x)=((e^((x+3)ln27))^(x/27)-9)/(3^x-27) , x < 3` and `f(x)=lambda(1-cos(x-3))/((x-3)tan(x-3))` if `lim_(x->3)f(x)` exist then `lmbda ` is

if f(x)=((e^((x+3)ln27))^(x/27)-9)/(3^x-27) , x 3 if lim_(x->3)f(x) exist then lmbda is

If f(x)={(((exp{(x+3)ln27})^(1/27[x])-9)/(3^x-27), x lt 3), (lamda.((1-cos(x-3)))/((x-3)tan(x-3)), x gt 3):} is continuous at x = 3, then the value of 9lambda must be

If 27^(x)=(9)/(3^(x)), find x

f(x)=x^(3)+27x+5

lim_(x rarr3)(x^(3)-27)/(x^(2)-9)

int((27)^(1+x)+9^(1-x))/(3^(x))

27^(x)=(9)/(3^(x)), Find the value of x

If 27^x=9/(3^x), find xdot

If 27^x=9/(3^x), find xdot

If f(x)=27x^(3) and g(x) =x^(1//3) . Then, find gof(x).