["STATEMENT_I: If ""x cosq"=y cos(1200+q)],[=z cos(q+2400)" then "xy+yz+zx=1],["STATEMENT_II"" cos a "+cos(1200+a)+],[cos(1200-a)=0]

If x=y cos((2 pi)/(3))=z cos((4 pi)/(3)), then xy+yz+zx=

If x=y cos((2pi)/(3))=z cos ((4pi)/(3)) then xy+yz+zx=

If xcostheta=ycos(theta+120^(@))=z cos (theta+240^(@)) then xy+yz+zx=

I : If x cos theta = y cos (120^@ + theta ) = z cos ( theta + 240^(@)) then xy+ yz+ zx=1 II : cos alpha + cos (120^(@) + alpha ) + cos (120^@ - alpha ) =0

Statement I: If x cos theta=y cos(120^(@)+theta)=z cos(theta+240^(@)) then xy+yz+zx=1 Statement II: cos alpha+cos(120^(@)+alpha)+cos(120^(@)alpha)=0 Which of the above statements is correct

x = cos 55^(@), y = cos 65^(@), z= cos 175^(@) " then " xy+yz+ zx=

x=cos55^(@),y=cos65^(@),z=cos175^(@) then xy+yz+xz=