Consider the sequence `u_n=sum_(r=1)^n r/2^r , n >= 1` then the `limit_(n->oo) u_n`

Find sum_(n=1)^n u_n if u_n=sum_(n=0)^n1/2^n .

If u(n)=prod_(r=0)^n(1+r^2/n^2)^r "then" lim_(nrarroo) (u)^((-4)/n^2

In a geometric series, the first term is a and common ratio is rdot If S_n denotes the sum of the terms and U_n=sum_(n=1)^n S_n ,then r S_n+(1-r)U_n equals (a) 0 b. n c. n a d. n a r

In a geometric series, the first term is a and common ratio is rdot If S_n denotes the sum of the terms and U_n=sum_(n=1)^n S_n ,then r S_n+(1-r)U_n equals a. 0 b. n c. n a d. n a r

In a geometric series , the first term is a and common ratio is r. If S_n denotes the sum of the n terms and U_n=Sigma_(n=1)^(n) S_n , then rS_n+(1-r)U_n equals

In a geometric series , the first term is a and common ratio is r. If S_n denotes the sum of the n terms and U_n=Sigma_(n=1)^(n) S_n , then rS_n+(1-r)U_n equals

lim_(n to oo) sum_(r=1)^(n) (1)/(n)e^(r//n) is

lim_(n to oo) sum_(r = 1)^(n) 1/n e^(r/n) is :

lim_(n to oo) sum_(r=1)^(n) (1)/(n)e^(r//n) is