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A pendulum bob on a 2 m string is displa...

A pendulum bob on a 2 m string is displaced `60^(@)` from the vertical and then released. What is the speed of the bob as it passes through the lowest point in its path

A

`sqrt(2)m//s`

B

`sqrt(9.8) m//s`

C

`4.43 m//s`

D

`1//sqrt(2) m//s`

Text Solution

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The correct Answer is:
C
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Knowledge Check

  • A pendulum bob on a 2 m string is displaced 60^(@) from the verticle and then released . What is the speed of the bob as it passes through the lowest point in its path?

    A
    `sqrt2 m//s`
    B
    `sqrt 9.8 m//s`
    C
    `4.43 m//s`
    D
    `1//sqrt2 m//s`
  • A simple pendulum of length 1m has bob of mass 100 g. It is displaced through an angle of 60^@ from the vertcal and then released. The kinetic energy of bob when it passes through the mean position is

    A
    `0.25J`
    B
    `0.5J`
    C
    `1.0J`
    D
    `1.4J`
  • A simple pendulum of bob mass m and length l is displaced from its mean position O to a point A and then released . If v is the velocity of the bob at O, h is the height of string of pendulum when bob passes through point O is /are (neglect friction )

    A
    `(2mgh)/(l)`
    B
    `2mg""(1+(h))/(l)`
    C
    `mg""(1+(2h))/(l)`
    D
    `mg""(1-(2h))/(l)`
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