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A body of mass 0.4 kg is whirled in a ve...

A body of mass 0.4 kg is whirled in a vertical circle making 2 rev/sec . If the radius of the circle is 2 m , then tension in the string when the body is at the top of the circle, is

A

`41.56 N`

B

`89.86 N`

C

`109.86 N`

D

`122.2 N`

Text Solution

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The correct Answer is:
To find the tension in the string when the body is at the top of the vertical circle, we can follow these steps: ### Step 1: Identify the given values - Mass of the body, \( m = 0.4 \, \text{kg} \) - Radius of the circle, \( r = 2 \, \text{m} \) - Frequency of revolution, \( f = 2 \, \text{rev/sec} \) ### Step 2: Calculate the angular velocity (\( \omega \)) The angular velocity in radians per second can be calculated using the formula: \[ \omega = 2\pi f \] Substituting the given frequency: \[ \omega = 2\pi \times 2 = 4\pi \, \text{rad/sec} \] ### Step 3: Calculate the linear velocity (\( v \)) The linear velocity can be calculated using the formula: \[ v = \omega \times r \] Substituting the values: \[ v = 4\pi \times 2 = 8\pi \, \text{m/s} \] ### Step 4: Calculate the centripetal force (\( F_c \)) The centripetal force required to keep the body moving in a circle is given by: \[ F_c = \frac{mv^2}{r} \] Substituting the values: \[ F_c = \frac{0.4 \times (8\pi)^2}{2} \] Calculating \( (8\pi)^2 \): \[ (8\pi)^2 = 64\pi^2 \] Now substituting this back into the equation: \[ F_c = \frac{0.4 \times 64\pi^2}{2} = 0.2 \times 64\pi^2 = 12.8\pi^2 \, \text{N} \] ### Step 5: Calculate the weight of the body (\( mg \)) The weight of the body is given by: \[ mg = 0.4 \times 10 = 4 \, \text{N} \] ### Step 6: Apply the forces at the top of the circle At the top of the circle, the tension (\( T \)) in the string and the weight of the body both act downwards. The centripetal force is provided by the sum of these two forces: \[ F_c = T + mg \] Rearranging for tension: \[ T = F_c - mg \] Substituting the values: \[ T = 12.8\pi^2 - 4 \] ### Step 7: Calculate the numerical value of tension Using \( \pi \approx 3.14 \): \[ \pi^2 \approx 9.86 \] Now substituting this into the equation: \[ T = 12.8 \times 9.86 - 4 \] Calculating: \[ T \approx 126.08 - 4 = 122.08 \, \text{N} \] ### Final Answer The tension in the string when the body is at the top of the circle is approximately: \[ \boxed{122.08 \, \text{N}} \]
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