A stone projected with a velocity u at an angle (theta )with the horizontal reaches maximum heights `H_(1)`. When it is projected with velocity u at an angle `(pi/2-theta)` with the horizontal, it reaches maximum height `H_(2)`. The relations between the horizontal range R of the projectile, `H_(1) and H_(2)`, is

Options

A. `R = 4sqrt(H_(1)H_(2))`
B. `R = 4(H_(1)-H_(2))`
C. `R = 4(H_(1)+H_(2))`
D. `R = (H_(1)^(2))/(H_(2)^(2))`

Answer

A