For a stationary wave, `t = 8 sin ((pix)/(20)) cos (50 pit)`. What is the distance between two successive antinode ?

The frequency of the progressive wave which form the stationary wave y=-4sin((pix)/(5)) cos (100pit) and the distance between two consecutive nodes are

For a stationary wave y = 10 sin ((pi x )/(4)) cos (2pi t ) metre, distance between two consecutive nodes is ...... m.

For a stationary wave y = 10 sin ((pi x)/15) cos (48 pi t) cm, the distance between a node and the nearest antinode is

The equation of a stationary wave is y = 2 sin ((pi x)/(15)) cos ( 48 pi t) . The distance between a node and its next antinode is.

The distance between any two successive nodes or antinodes is

For a stationary wave y = 4 sin (pix//15) cos(96 pi t) . This distance between a node and the next antinode is:

The equation of a stationary wave is given by y=0.5 cm cos (2pi x) sin (100 pit) . The distance between its successive nodes and antinods is