The momentum of `alpha`-particles moving in a circular path of radius 10 cm in a perpendicular magnetic field of 0.05 tesla will be :

An alpha -particle moves in a circular path of radius 0.83 cm in the presence of a magnetic field of 0.25 Wb//m^(2) . What is the de Broglie wavelength associated with the particle?

An alpha -particle moves in a circular path of radius 1 cm in a uniform magnetic field of 0 .1 25 T . The de-Broglie wavelength associated with the alpha - particle is

A proton moves on a circular path of radius 6.6 × 10^(-3) m in a perpendicular magnetic field of 0.625 tesla. The De broglie wavlength associated with the proton will be :

An alpha - particle moves in a circular path of radius 0.83cm in the presence of a magnetic field of 0.25Wb//m^2 .The de-broglie wavelength associated with the particle will be:

A alpha -parhticle moves in a circular path of radius 0.83 cm in the presence of a magnetic field of 0.25 Wb//m^(2) . The de-Broglie wavelength assocaiated with the particle will be

A alpha -parhticle moves in a circular path of radius 0.83 cm in the presence of a magnetic field of 0.25 Wb//m^(2) . The de-Broglie wavelength assocaiated with the particle will be

A alpha -parhticle moves in a circular path of radius 0.83 cm in the presence of a magnetic field of 0.25 Wb//m^(2) . The de-Broglie wavelength assocaiated with the particle will be

A alpha -parhticle moves in a circular path of radius 0.83 cm in the presence of a magnetic field of 0.25 Wb//m^(2) . The de-Broglie wavelength assocaiated with the particle will be

Assertion: If a charged particle is moving on a circular path in a perpendicular magnetic field, the momentum of the particle is not changing. Reason: Velocity of the particle in not changing in the magnetic field.