If `alpha, beta, gamma` are the roots of `x^3 + x^2 + x + 1 = 0` then

If alpha, beta ,gamma are the roots of 2x^(3) - 5x^(2) + 3x - 1 = 0 then (1)/(alpha beta ) + (1)/(beta gamma) + (1)/(gamma alpha) =

If alpha , beta , gamma are the roots of x^3 + 2x^2 + 3x +8=0 then ( alpha + beta ) ( beta + gamma) ( gamma + alpha ) =

If alpha , beta , gamma are the roots of x^3 + 2x^2 + 3x +8=0 then ( alpha + beta ) ( beta + gamma) ( gamma + alpha ) =

If alpha,beta, gamma are the roots of 4x^(3) - 6x^(2) + 7x + 3 = 0 then alpha beta + alpha beta + alpha gamma =

If alpha , beta , gamma are the roots of x^3 +2x^2 -3x -1=0 then alpha^(-2) + beta^(-2) + gamma^(-2)=