If `A, B in (0,pi/2)` such that `3sin^2A+2sin^2B=1` and `3sin2A-2sin2B=0`, find the value of `A+B`

Select the correct options from the given alternatives.Let 0 < A , B < pi/2 satisfying the equation 3sin^2A+2sin^2B=1 and 3sin2A-2sin2B=0 then A+2B is equal to………..

If A, B are acute positive angles satisfying the equations 3sin^(2)A+2sin^(2)B=1 and 3sin2A-2sin2B=0 , then find A+2B .

If Aa n dB are acute positive angles satisfying the equations 3sin^2A+2sin^2B=1 and 3sin2A-2sin2B=0, then A+2B is equal to (a) pi (b) pi/2 (c) pi/4 (d) pi/6

Let 0

If AandB are acute positive angles satisfying the equations 3sin^(2)A+2sin^(2)B=1 and 3sin2A-2sin2B=0, then A+2B is equal to (a) pi (b) (pi)/(2) (c) (pi)/(4) (d) (pi)/(6)

Let 0 lt A, B lt (pi)/(2) satisfying the equation 3 sin ^(2) A + 2 sin ^(2) B =1 and 3 sin 2A - 2 sin B =0 then A +2B =

If A and B are acute positive angles satisfying the equations 3sin^(2)A+2sin^(2)B=1 and 3sin2A-2sin 2B=0 , then A+2B is equal to

If A and B are acute positive angles satisfying the equations 3 "sin"^(2) A + 2"sin"^(2)B =1 " and " 3"sin"2A-2 "sin" 2B = 0, "then " A +2B =

If A and B are acute positive angles satisfying the equations 3 sin^(2)A+2sin^(2) B=1 and 3 sin2A-2 sin 2B=0 , then A+2B is equal to