If the curves `(x^2)/(a^2)+(y^2)/(b^2)=1 and (x^2)/(l^2)-(y^2)/(m^2)=1`cut each other orthogonally then.....

If the curves (x^(2))/(l^(2))+(y^(2))/(m^(2))=1 and (x^(2))/(64)+(y^(2))/(25)=1 cut each other orthogonally then l^(2)-m^(2)

If the curves x^2/a^2+y^2/b^2=1 and x^2/l^2-y^2/m^2=1 cut each other orthagonally, then

If the curves (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 and (x^(2))/(c^(2))+(y^(2))/(d^(2))=1 intersect orthogonally, then

If the curves (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 and (x^(2))/(c^(2))+(y^(2))/(d^(2))=1 intersect orthogonally, then

If the curves x^2/a^2+y^2/b^2=1 and x^2/25+y^2/16=1 cut each other orthagonally, then a^2-b^2 =

If the curves ax^(2) + by^(2) =1 and a_(1) x^(2) + b_(1) y^(2) = 1 intersect each other orthogonally then show that (1)/(a) - (1)/(b) = (1)/(a_(1)) - (1)/(b_(1))

If the curve ax^(2) + 3y^(2) = 1 and 2x^2 + 6y^2 = 1 cut each other orthogonally then the value of 2a :

The curves 2x^(2) + 3y^(2) = 1 and cx^(2) + 4y^(2) = 1 cut each other orthogonally then the value of c is: