`x= (sqrt(a+26)+sqrt(a-26))/(sqrt(a+26)-sqrt(a-26))` then show that `6x^2-ax+6=0`

sqrt(26)xxsqrt(6.24)xxsqrt(102)=?

root(3)(26-15sqrt(3))=

If the value of the determinant |{:(3sqrt(6),-4sqrt(2)),(5sqrt(3),x):}| is 26sqrt(6) , find the value of x .

If sin h^(-1)(x)=log_(e)(5+sqrt(26)) then x=

The line segment joining the points A,B makes projection 1,4,3 on x,y,z axes respectively then the direction cosiners of AB are (A) 1,4,3 (B) 1/sqrt(26),4/sqrt(26),3/sqrt(26) (C) (-1)/sqrt(26, 4/sqrt(26),3/sqrt(26) (D) 1/sqrt(26),(-4)/sqrt(26),3/(sqrt(26)

The line segment joining the points A,B makes projection 1,4,3 on x,y,z axes respectively then the direction cosiners of AB are (A) 1,4,3 (B) 1/sqrt(26),4/sqrt(26),3/sqrt(26) (C) (-1)/sqrt(26, 4/sqrt(26),3/sqrt(26) (D) 1/sqrt(26),(-4)/sqrt(26),3/(sqrt(26)

Show that the square to (sqrt(26-15sqrt(3)))/(5sqrt(2)-sqrt(38+5sqrt(3))) is a rational number.

26. Prove that the points O(0,0,0),A(2.0,0),B(1,sqrt(3),0) and C(1,(1)/(sqrt(3)),(2sqrt(2))/(sqrt(3))) are the vertices of a regular tetrahedron...

Show that the square to (sqrt(26-15sqrt(3)))//(5sqrt(2)-sqrt(38+5sqrt(3))) is a rational number.