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A ball of mass m moves with speed v and ...

A ball of mass m moves with speed `v` and it strikes normally with a wall and reflected back normally, if its time of contact with wall is `t` then find force exerted by ball on wall

A

`(2mv)/(t)`

B

`(mv)/(t)`

C

mvt

D

`(mv)/(2t)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the force exerted by the ball on the wall when it strikes and reflects back, we can follow these steps: ### Step 1: Understand the Initial and Final Momentum When the ball strikes the wall, it has an initial momentum given by: \[ p_{\text{initial}} = mv \] where \( m \) is the mass of the ball and \( v \) is its velocity. After striking the wall and reflecting back, the ball's velocity becomes \( -v \) (the negative sign indicates the direction is opposite). Thus, the final momentum is: \[ p_{\text{final}} = m(-v) = -mv \] ### Step 2: Calculate the Change in Momentum The change in momentum (\( \Delta p \)) can be calculated as: \[ \Delta p = p_{\text{final}} - p_{\text{initial}} \] Substituting the values we found: \[ \Delta p = (-mv) - (mv) = -mv - mv = -2mv \] ### Step 3: Relate Change in Momentum to Force The force exerted by the ball on the wall can be calculated using the formula: \[ F = \frac{\Delta p}{\Delta t} \] where \( \Delta t \) is the time of contact with the wall, which is given as \( t \). Substituting the change in momentum: \[ F = \frac{-2mv}{t} \] ### Step 4: Determine the Magnitude of the Force Since force is typically expressed as a positive value when discussing magnitude, we can write: \[ F = \frac{2mv}{t} \] ### Final Answer The force exerted by the ball on the wall is: \[ F = \frac{2mv}{t} \] ---
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