A ball of mass 400 gm is dropped from a ...

A ball of mass 400 gm is dropped from a height of 5 m . A boy on the ground hits the ball vertically upwards with a bat with an average force of 100 newton so that it attains a vertical height of 20 m . The time for which the ball remains in contact with the bat is `[g=10m//s^(2)]`

`0.12s`

`0.08` s

`0.04` s

12 s

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A ball of mass 400 gm is dropped from a height of 5 m. A boy on the ground hits the ball vertically upwards with a bat with an average force of 100 newton so that it attains a vertical velocity of 20 m/s. The time for which the ball remains in contact with the bat is (g=10m//s^(2))

A ball of the mass 400gm is dropped from a height of 5m. A boy on the ground hits the ball vertically upwards with a bat with an average force of 100N so that it attains a vertical height of 20m. The time for which the ball remains in contect with the bat is [ g=10m//s^(-2)]

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A ball is thrown vertically upward with a velocity of 20 m/s. Calculate the maximum height attain by the ball.

A ball is thrown vertically upward attains a maximum height of 45 m. The time after which velocity of the ball become equal to half the velocity of projection ? (use g = 10 m//s^(2) )

A ball is dropped from a height 64m above the ground and every time it hits the ground it rises to a height equal to half of the previous height.The height attained after it hits the ground for the 16h time is

A ball is dropped from a height 64 m above the ground and every time it hits the ground it rises to a height equal to half of the previous. What is the height attained after it hits the ground for the 16^(th) time?

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