It is easier to draw up a wooden block along an inclined plane than to haul it vertically, principally because

Options

A. The friction is reduced
B. The mass becomes smaller
C. Only a part of the weight has to be overcome
D. ‘ g ’ becomes smaller

Answer

To solve the question of why it is easier to draw up a wooden block along an inclined plane than to haul it vertically, we can analyze the forces involved in both scenarios.

### Step-by-Step Solution:

1. **Understanding the Forces Acting on the Block**:
- When the block is on a flat surface, the only force acting against the pulling force is its weight, which is given by \( W = Mg \), where \( M \) is the mass of the block and \( g \) is the acceleration due to gravity.

2. **Forces on an Inclined Plane**:
- When the block is on an inclined plane at an angle \( \theta \), the weight of the block can be resolved into two components:
- Perpendicular to the incline: \( W_{\perpendicular} = Mg \cos(\theta) \)
- Parallel to the incline: \( W_{\parallel} = Mg \sin(\theta) \)

3. **Comparing Forces**:
- When pulling the block vertically, the entire weight \( W = Mg \) must be overcome.
- However, when pulling the block up the incline, only the parallel component \( W_{\parallel} = Mg \sin(\theta) \) needs to be overcome.

4. **Conclusion**:
- Since \( Mg \sin(\theta) < Mg \) for any angle \( \theta > 0 \), it is evident that less force is required to pull the block up the incline than to lift it vertically. This is the principal reason why it is easier to draw the block up an inclined plane.

5. **Friction Consideration**:
- Additionally, friction may play a role in this scenario. On an inclined plane, the normal force is reduced (since \( N = Mg \cos(\theta) \)), which in turn reduces the frictional force acting against the motion. Thus, the combined effect of reduced weight component and friction makes it easier to pull the block up the incline.

### Final Answer:
It is easier to draw up a wooden block along an inclined plane than to haul it vertically principally because only a part of the weight (the component along the incline) has to be overcome, and the friction is reduced.