A particale moves under the effect of a ...

A particale moves under the effect of a force `F = Cs` from `x = 0` to `x = x_(1)`. The work down in the process is

A

`Cx_(1)^(2)`

B

`(1)/(2)Cx_(1)^(2)`

C

`Cx_(1)`

D

zero

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The correct Answer is:

B

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