The kinetic energy passessed by a body o...

The kinetic energy passessed by a body of mass m moving with a velocity v is equal to `(1)/(2)mv^(2)`, provided

The body moves with velocities comparable to that of light.

The body moves with velocities negligible compared to the speed of light

The body moves with velocities greater than that of light

None of the above statement is correcst

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Relation between kinetic energy and momentum Let us consider a body of mass 'm' having a velocity 'v', then momentum of the body P = mass xx velocity P = m xx v rArr v = (P)/(m) " "...(1) From definition, kinetic energy (K.E) of the body K.E = (1)/(2) mv^(2)" "...(2) Now putting the value of (1) in (2) we have K.E = (1)/(2)m ((P)/(m))^(2) K.E. = (1)/(2)m (P^(2))/(m^(2)) = (1)/(2) (P^(2))/(m) = (P^(2))/(2m)" "...(3) Thus we can write P^(2) = 2m xx K.E rArr P = sqrt(2m xx K.E) Thus momentum = sqrt(2 xx "mass" xx "kinetic energy") The kinetic energy of a given body is doubled. Its momentum will

ERRORLESS -WORK, ENERGY, POWER & COLLISION-Assertion

The kinetic energy passessed by a body of mass m moving with a velocit...
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