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1 a.m.u is equivalent to...

1 a.m.u is equivalent to

A

`1.6xx10^(-12)`joule

B

`1.6xx10^(-19)` joule

C

`1.5xx10^(-10)` joule

D

`1.5xx10^(-19)` joule

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The correct Answer is:
To find the equivalent of 1 atomic mass unit (amu) in joules, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Definition of amu**: - An atomic mass unit (amu) is defined as one twelfth of the mass of a carbon-12 atom. 2. **Calculate the Mass of 1 amu in grams**: - Since 1 mole of carbon-12 weighs 12 grams and contains Avogadro's number of atoms (approximately \(6.022 \times 10^{23}\)), the mass of one carbon-12 atom is: \[ \text{Mass of 1 atom} = \frac{12 \text{ grams}}{6.022 \times 10^{23}} \approx 1.99 \times 10^{-24} \text{ grams} \] - Therefore, 1 amu is approximately \(1.66 \times 10^{-24}\) grams. 3. **Convert grams to kilograms**: - To convert grams to kilograms, we divide by 1000: \[ 1 \text{ amu} = 1.66 \times 10^{-24} \text{ grams} = 1.66 \times 10^{-27} \text{ kg} \] 4. **Use Einstein's equation to find energy**: - According to Einstein's equation \(E = mc^2\), where \(c\) is the speed of light (\(3 \times 10^8 \text{ m/s}\)): \[ E = (1.66 \times 10^{-27} \text{ kg}) \times (3 \times 10^8 \text{ m/s})^2 \] - Calculate \(c^2\): \[ c^2 = (3 \times 10^8)^2 = 9 \times 10^{16} \text{ m}^2/\text{s}^2 \] 5. **Calculate the energy in joules**: - Now substitute \(c^2\) back into the energy equation: \[ E = 1.66 \times 10^{-27} \text{ kg} \times 9 \times 10^{16} \text{ m}^2/\text{s}^2 \] \[ E \approx 1.494 \times 10^{-10} \text{ joules} \] 6. **Final Result**: - Therefore, we can conclude that: \[ 1 \text{ amu} \approx 1.5 \times 10^{-10} \text{ joules} \]
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When slow neutrons are incident on a target containing underset(92)overset(235).U , a possible fission reaction is underset(92)overset(235).U+underset(0)overset(1).nrarr underset(56)overset(141).Ba+underset(36)overset(92).Kr+3_(0)^(1)n Estimate the amount of energy released using the following data Given, mass of underset(92)overset(235).U=235.04 amu , mass of underset(0)overset(1).n=1.0087 amu , mass of underset(56)overset(141).Ba=140.91 amu , mass of underset(36)overset(92).Kr=91.926 amu , and energy equivalent to 1 amu=931 MeV.

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