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A body falling from a height of 10m rebo...

A body falling from a height of 10m rebounds from hard floor. If it loses 20% energy in the impact, then coefficient of restitution is

A

0.89

B

0.56

C

0.23

D

0.18

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The correct Answer is:
To solve the problem step by step, we will follow these steps: ### Step 1: Calculate the velocity just before impact When a body falls from a height \( h \), its velocity just before impact can be calculated using the equation of motion: \[ v = \sqrt{2gh} \] Where: - \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \)) - \( h \) is the height (10 m in this case) Substituting the values: \[ v = \sqrt{2 \times 9.81 \times 10} = \sqrt{196.2} \approx 14.0 \, \text{m/s} \] ### Step 2: Calculate the initial kinetic energy The initial kinetic energy (KE_initial) just before the impact can be calculated using: \[ KE_{\text{initial}} = \frac{1}{2} mv^2 \] Substituting \( v \): \[ KE_{\text{initial}} = \frac{1}{2} m (14.0)^2 = \frac{1}{2} m \times 196 \approx 98m \, \text{J} \] ### Step 3: Determine the energy lost during impact It is given that the body loses 20% of its energy during the impact. Therefore, the energy lost (E_lost) is: \[ E_{\text{lost}} = 0.2 \times KE_{\text{initial}} = 0.2 \times 98m = 19.6m \, \text{J} \] ### Step 4: Calculate the final kinetic energy after impact The final kinetic energy (KE_final) after the impact can be calculated as: \[ KE_{\text{final}} = KE_{\text{initial}} - E_{\text{lost}} = 98m - 19.6m = 78.4m \, \text{J} \] ### Step 5: Relate final kinetic energy to final velocity Using the final kinetic energy to find the final velocity (\( v' \)): \[ KE_{\text{final}} = \frac{1}{2} mv'^2 \] Substituting for KE_final: \[ 78.4m = \frac{1}{2} mv'^2 \] Canceling \( m \) from both sides: \[ 78.4 = \frac{1}{2} v'^2 \implies v'^2 = 156.8 \implies v' = \sqrt{156.8} \approx 12.5 \, \text{m/s} \] ### Step 6: Calculate the coefficient of restitution The coefficient of restitution (e) is defined as the ratio of the velocity of separation to the velocity of approach: \[ e = \frac{v'}{v} \] Substituting the values of \( v' \) and \( v \): \[ e = \frac{12.5}{14.0} \approx 0.893 \] ### Final Answer The coefficient of restitution is approximately \( 0.89 \). ---
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