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A bullet of mass m moving with velocity ...

A bullet of mass `m` moving with velocity `v` strikes a block of mass `M` at rest and gets embedded into it. The kinetic energy of the composite block will be

A

`(1)/(2)mv^(2)xx(m)/((m+M))`

B

`(1)/(2)mv^(2)xx(M)/((m+M))`

C

`(1)/(2)mv^(2)xx((M+m))/(M)`

D

`(1)/(2)Mv^(2)xx(m)/((m+M))`

Text Solution

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The correct Answer is:
A
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