A horizontal force of 5 N is required to maintain a velocity of 2 m / s for a block of 10 kg mass sliding over a rough surface. The work done by this force in one minute is

Options

A. 600 J
B. 60 J
C. 6 J
D. 6000 J

Answer

To solve the problem, we need to calculate the work done by a horizontal force of 5 N on a block of mass 10 kg sliding over a rough surface at a constant velocity of 2 m/s for one minute.

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Force (F) = 5 N
- Velocity (v) = 2 m/s
- Time (t) = 1 minute = 60 seconds

2. **Calculate the Displacement:**
- Displacement (d) can be calculated using the formula:
\[ d = v \times t \]
- Substituting the values:
\[ d = 2 \, \text{m/s} \times 60 \, \text{s} = 120 \, \text{m} \]

3. **Calculate the Work Done:**
- Work done (W) by the force can be calculated using the formula:
\[ W = F \times d \times \cos(\theta) \]
- Since the force is applied horizontally and the displacement is also horizontal, the angle (\(\theta\)) between the force and displacement is 0 degrees. Therefore, \(\cos(0) = 1\).
- Substituting the values:
\[ W = 5 \, \text{N} \times 120 \, \text{m} \times 1 = 600 \, \text{J} \]

4. **Final Answer:**
- The work done by the force in one minute is **600 Joules**.