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A bag of sand of mass M is suspended by ...

A bag of sand of mass M is suspended by a string. A bullet of mass m is fired at it with velocity v and gets embedded into it. The loss of kinetic energy in this process is

A

`(1)/(2)mv^(2)`

B

`(1)/(2)mv^(2)xx(1)/(M+m)`

C

`(1)/(2)mv^(2)xx(M)/(m)`

D

`(1)/(2)mv^(2)((M)/(M+m))`

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • A bag of sand of mass m is suspended by a rope. A bullet of mass (m)/(20) is fired at it with a velocity vand gets embedded into it. The velocity of the bag finally is

    A
    `(v)/(20)xx21`
    B
    `(20v)/(21)`
    C
    `(v)/(20)`
    D
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  • A bag of sand of mass M is suspended by a roap. A bullet of mass m. traveling with speed v gets. embedded in it. The loss of kinetic energy is

    A
    `Mmv //(M + m)`
    B
    `(M + m)//Mmv`
    C
    `(Mmv^2)/(2(M + m))`
    D
    `(2(M + m))/(Mv^2)`
  • A block of wood of mass 3M is suspended by a string of length (10)/(3) m . A bullet of mass M hits it with a certain velocity and gets embedded in it. The block and the bullet swing to one side till the string makes 120^@ with the initial position. the velocity of the bullet is (g=10 ms^(-2)) .

    A
    `(40)/(sqrt(3)) ms^(-1)`
    B
    `20 ms^(-1)`
    C
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    D
    `40 ms^(-1)`.
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