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If sigma be the surface tension, the wo...

If `sigma ` be the surface tension, the work done in breaking a big drop of radius R in n drops of equal radius is

A

`Rn^(2//3) sigma`

B

`(n^(2//3)-1)Rsigma`

C

`(n^(1//3)-1) R sigma`

D

`4piR^(2)(n^(1//3)-1) sigma`

Text Solution

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The correct Answer is:
D
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ERRORLESS -SURFACE TENSION-Exercise
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  2. The work done in increasing the size of a soap film from 10 cm × 6 cm ...

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  3. If sigma be the surface tension, the work done in breaking a big drop...

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  4. A big drop of radius R is formed by 1000 small droplets of water, then...

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  5. When 10^(6) small drops coalesce to make a larger drop them the drop

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  6. Which of the following statements are true in case when two water drop...

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  7. 8000 identical water drops combine together to form a big drop. Then t...

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  8. The surface energy of liquid film on a ring of area 0.15 m^(2) is (sur...

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  9. 8 mercury drops coalesce to form one mercury drop, the energy changes ...

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  10. If work done in increasing the size of a soap film from 10 cm x 6 cm t...

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  11. A mercury drop of radius 1 cm is sprayed into 10^(6) drops of equal s...

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  12. When two small bubbles join to form a bigger one, energy is

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  13. A film of water is formed between two straight parallel wires of lengt...

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  14. A drop of mercury of radius 2 mm is split into 8 identical droplets. F...

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  15. Two small drop of mercury, each of radius R coalesce in from a simple ...

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  16. Radius of a soap bubble is increased from R to 2 R work done in this p...

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  17. The work done in blowing a soap bubble of radius 0.2 m is (the surface...

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  18. A liquid film is formed in a loop of area 0.05 m 2. Increase in its p...

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  19. In order to float a ring of area 0.04 m in a liquid of surface tension...

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  20. If two soap bubbles of equal radii r coalesce then the radius of curva...

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