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If work done in increasing the size of a soap film from 10 cm x 6 cm to 10 cm x 11 cm is `2xx10^(-4) J`, then the surface tension is

A

`2xx10^(-2) Nm^(-1)`

B

`2xx10^(-4) Nm^(-1)`

C

`2xx10^(-6) Nm^(-1)`

D

`2xx10^(-8) Nm^(-1)`

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The correct Answer is:
A
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ERRORLESS -SURFACE TENSION-Exercise
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  8. Two small drop of mercury, each of radius R coalesce in from a simple ...

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  9. Radius of a soap bubble is increased from R to 2 R work done in this p...

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  10. The work done in blowing a soap bubble of radius 0.2 m is (the surface...

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  11. A liquid film is formed in a loop of area 0.05 m 2. Increase in its p...

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  12. In order to float a ring of area 0.04 m in a liquid of surface tension...

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  13. If two soap bubbles of equal radii r coalesce then the radius of curva...

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  14. A liquid will not wet the surface of a solid if the angle of contact ...

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  15. The meniscus of mercury in the capillary tube is

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  16. When the temperature increased the angle of contact of a liquid

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  17. The angle of contanct between glass and mercury is

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  18. A mercury drop does not spread on a glass plate because the angle of c...

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  19. A liquid is coming out from a vertical tube. The relation between the ...

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