Emf of a cell corresponding to the reaction:-
`Zn(s) +2H^(+) (aq) rarr Zn^(2+)(aq) [0.1M] +H_(2)(g) [1.0atm]` is `0.49V` at `25^(@)C, E_(Zn^(2+)//Zn)^(@) = - 0.76 V`.
The `pH` of solution in cathode chamber is.

Complete the reaction: Zn(s)+2H^(+)(aq)to

The emf of a cell corresponding to the reaction. Zn(s)+ 2H^(+)(aq)rightarrow Zn^(2+)(0.1M)+H_(2) (g,1atm) is 0.28 V at 25^(@) C . Calculate pH of the solution.

The emf of a cell corresponding to the reaction, Zn(s) + 2H^(+) ( aq) rarr Zn^(2+) ( 0.1 M ) + H_(2) ( g , 1 atm) is 0.28 V at 25^(@)C . Write the half-cell reaction and calculate the pH of the solution at the hydrogen electrode. E_(Zn^(2+)//Zn)^(@) = - 0.76V, E_(H^(+) //H_(2))^(@) = 0

The emf of a cell corresponding to the reaction Zn +2H^(+)(aq) rarr Zn^(2+) (0.1M) +H_(2)(g) 1 atm is 0.28 volt at 25^(@)C . Calculate the pH of the solution at the hydrogen electrode. E_(Zn^(2+)//Zn)^(@) =- 0.76 volt and E_(H^(+)//H_(2))^(@) = 0

The emf of a cell corresponding to the reaction Zn +2H^(+)(aq) rarr Zn^(2+) (0.1M) +H_(2)(g) 1 atm is 0.28 volt at 25^(@)C . Calculate the pH of the solution at the hydrogen electrode. E_(Zn^(2+)//Zn)^(@) =- 0.76 volt and E_(H^(+)//H_(2))^(@) = 0

The emf of a cell corresponding to the reaction Zn +2H^(+)(aq) rarr Zn^(2+) (0.1M) +H_(2)(g) 1 atm is 0.28 volt at 25^(@)C . Calculate the pH of the solution at the hydrogen electrode. E_(Zn^(2+)//Zn)^(@) =- 0.76 volt and E_(H^(+)//H_(2))^(@) = 0

Write the half reactions for the following redox reaction. Zn(s) + 2H^+ (aq) rarr Zn^(2+) (aq) + H_2(g)

The e.m.f. of a cell corresponding to the reaction : Zn_((s))+2H_((aq.))^(+) rarr underset((0.1 M))(Zn^(2+))+underset((1 atm))(H_(2(g)) is 0.28 V at 25^(@)C and E_(Zn//Zn^(2+))^(@) = 0.76V . (i) Write half cell reactions. (ii) Calculate pH of the solution at H electrode.

Identify the limiting reagent in the above reaction. Zn_(s) + HCl_(aq) rarr ZnCl_(2(aq)) + H_(2(g))