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If f(x+2y,x-2y)=xy then f(x,y) is equal ...

If `f(x+2y,x-2y)=xy` then f(x,y) is equal to

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`f(x+2y,x-2y) = xy`
Let `x+2y = a ->(1)`
Let `x-2y = b ->(2)`
Adding `(1)` and `(2)`,
`x+2y+x-2y = a+b => x = (a+b)/2`
Subtracting `(1) - (2)`,
`x+2y-x+2y = a-b => y = (a-b)/4`
`:. f(a,b) = ((a+b)/2)((a-b)/4) = (a^2-b^2)/8`
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