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Two particles of equal mass (m) each mov...


Two particles of equal mass (m) each move in a circle of radius (r) under the action of their mutual gravitational attraction find the speed of each particle.

A

`v=1/(2R) sqrt(1/(GM))`

B

`v=sqrt((Gm)/(2R))`

C

`v=1/2 sqrt((Gm)/R)`

D

`v=sqrt((4Gm)/R)`

Text Solution

Verified by Experts

The correct Answer is:
C
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