Home
Class 11
PHYSICS
The gravitional force between two point ...

The gravitional force between two point masses `m_(1)` and `m_(2)` at separation `r` is given by `F=k (m_(1)m_(2))/r^(2)`
The constant `k`

A

Depends on system of units only

B

Depends on medium between masses only

C

Depends on both (a) and (b)

D

Is independent of both (a) and (b)

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    ERRORLESS |Exercise Acceleration Due to Gravity|87 Videos

  • GRAVITATION

    ERRORLESS |Exercise Gravitation Potential, Energy and Escape Velocity|70 Videos

  • FRICTION

    ERRORLESS |Exercise MCQ S|125 Videos

  • MOTION IN ONE DIMENSION

    ERRORLESS |Exercise Motion In One Dimension|24 Videos

Similar Questions

Explore conceptually related problems

The gravitational force between two point masses m_(1) and m_(2) at separation r is given by F = k(m_(1) m_(2))/(r^(2)) The constant k doesn't

The electrostatic force between two point charges q_(1) and q_(2) at separation r is given by F= k. (q_(1)q_(2))/(r^(2)) . The constant k

Gravitational force between two objects with mass m_(1)" and "m_(2) kept r distance apart is given as F_(G)= (Gm_(1)m_(2))/(r^2) , where G is gravitational constant. Express the relative error in F_(G) .

Assertion : The centres of two cubes of masses m_(1) and m_(2) are separated by a distance r. The gravitational force between these two cubes will be (Gm_(1)m_(2))/(r^(2)) Reason : According to Newton's law of gravitation, gravitational force between two point masses m_(1) and m_(2) separated by a distance r is (Gm_(1)m_(2))/(r^(2)) .

What is the dimensional formula of (a) volume (b) density and (c ) universal gravitational constant 'G' . The gravitational force of attraction between two objects of masses m and m separated by a distance d is given by F = (G m_(1) m_(2))/(d^(2)) Where G is the universal gravitational constant.

F is the gravitational force between two point masses m_(1) and m_(2) , separated by a distance d. A point mass 2m_(1) is then brought near m_(1) . What is the total force on m_(2) ?

Assertion : Mass of the rod AB is m_(1) and of particle P is m_(2) . Distance between centre of rod and particle is r. Then the gravitational force between the rod and the particle is F=(Gm_(1)m_(2))/(r^(2)) Reason : The relation F=(Gm_(1)m_(2))/(r^(2)) can be applied directly only to find force between two particles.

Supposing Newton's law of gravitation for gravitation forces F_(1) and F_(2) between two masses m_(1) and m_(2) at positions r_(1) and r_(2) read where M_(0) is a constant of dimension of mass, r_(12) = r_(1) - r_(2) and n is a number. In such a case,

According to Newton's law of gravitation , the force F between tow bodies of masses m_1 and m_2 placed at a distance of 'r' form each other is given as F = G xx (m_(1)xx m_(2))/r_(2) , where G is the universal gravitional constant. Find the units of G in both C.G.S. and S.I. system.

If gravitational attraction between two points masses be given by F=G(m_(1)m_(2))/(r^(n)) . Then the period of a satellite in a circular orbit will be proportional to

ERRORLESS -GRAVITATION-SET
  1. The gravitional force between two point masses m(1) and m(2) at separa...

    Text Solution

    |

  2. Two identical spheres are placed in contact with each other. The force...

    Text Solution

    |

  3. Suppose that the force of earth's gravity suddenly disappears, choose ...

    Text Solution

    |

  4. An earth satellite is moved from one stable circular orbit to another ...

    Text Solution

    |

  5. Two planets revolve round the sun with frequencies N(1) and N(2) revol...

    Text Solution

    |

  6. There is no atomosphere on moon because

    Text Solution

    |

  7. Two heavenly bodies s1 & s2 not far off from each other, revolve in or...

    Text Solution

    |

  8. The mass of the moon is about 1.2% of the mass of the earth. Compared ...

    Text Solution

    |

  9. A clock S is based on oscillations of a spring and clock P is based on...

    Text Solution

    |

  10. Consider earth to be a homogeneous sphere. Scientist A goes deep down ...

    Text Solution

    |

  11. The mass of the moon is 1/81 of the earth but the gravitational pull i...

    Text Solution

    |

  12. A weight is suspended from the ceiling of a lift by a spring balance. ...

    Text Solution

    |

  13. If a planet consits of a satellite whose mass and radius were both hal...

    Text Solution

    |

  14. At a given place where acceleration due to gravity is 'g' m//sec^(2), ...

    Text Solution

    |

  15. g(e) and g(p) denote the acceleration due to gravity on the surface of...

    Text Solution

    |

  16. If the value of g at the surface of the earth is 9.8 m//sec^(2), then ...

    Text Solution

    |

  17. The acceleration due to gravity about the earth's surface would be hal...

    Text Solution

    |

  18. A pendulum clock is set to give correct time at the sea level. This cl...

    Text Solution

    |

  19. At some point the gravitational potential and also the gravitational f...

    Text Solution

    |

  20. A body falls freely under gravity. Its speed is v when it has lost an ...

    Text Solution

    |

  21. The ratio of the radius of the earth to that of moon is 10. The ratio ...

    Text Solution

    |