Home
Class 11
PHYSICS
The orbital velocity of a planet revolvi...

The orbital velocity of a planet revolving close to earth's surface is

A

`sqrt(2gR)`

B

`sqrt(gR)`

C

`sqrt((2g)/R)`

D

`sqrt(g/R)`

Text Solution

Verified by Experts

The correct Answer is:
B
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • GRAVITATION

    ERRORLESS |Exercise Kepler’s Laws of Planetary Motion|51 Videos
  • GRAVITATION

    ERRORLESS |Exercise CT|18 Videos
  • GRAVITATION

    ERRORLESS |Exercise Gravitation Potential, Energy and Escape Velocity|70 Videos
  • FRICTION

    ERRORLESS |Exercise MCQ S|125 Videos
  • MOTION IN ONE DIMENSION

    ERRORLESS |Exercise Motion In One Dimension|24 Videos

Similar Questions

Explore conceptually related problems

If the Earth were a homogenous sphere of wood of density 800 kg/ m^(3) . What would be (i)the acceleration due to gravity on the Earth's surface ? (ii) the critical velocity of a satellite orbiting close to its surface ?

If viscosity of air is taken into account, then the orbital velocity of the satellite moving close to earth

Knowledge Check

  • If V_e is the escape velocity and V_0 is orbital velocity of a satellite for orbit close to the earth's surface. Then these are related by

    A
    `V_0 = sqrt(2) V_e,`
    B
    `V_0 = V_e`,
    C
    `V_e = (V_0)/(2)`
    D
    `V_e = sqrt(2)V_0`
  • The orbital velocity of a body close to the earth's surface is

    A
    `8 "kms"^(-1)`
    B
    `11.2 "kms"^(-1)`
    C
    `3 xx 10^(8) "ms"^(-1)`
    D
    `2.2 xx 10^(3) "kms"^(-1)`
  • If v_(e) is escape velocity and v_(0) , is orbital velocity of satellite for orbit close to the earth's surface. Then are related by

    A
    `v_(0)=sqrt(2)v_(e)`
    B
    `n_(0)=n_(e)`
    C
    `v_(e)=(v_(0))/2`
    D
    `v_(e)=sqrt(2)v_(0)`
  • Similar Questions

    Explore conceptually related problems

    The orbital velocity of a satellite close to the earth is v. Then the orbital velocity at a height (1//4)^("th") of earth's radius is

    Question Stimulus :- The orbital speed of a satellite revolve very near to earth surface is-

    If rho is the mean density of the earth and R is its radius, then the critical speed of a satellite revolving very close to the surface of earth is :

    If g_(h) is the acceleration due to gravity at a height h above the earth's surface and R is the radius of the earth then, the critical velocity of a satellite revolving round the earth in a circular orbit at a height h is equal to

    If V_(o) be the orbital velocity of a satellite in a circular orbit close to earth's surface and V_(e ) is the escape velocity for the earth ,relation between the two is :