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A log of wood of mass 120 Kg floats in w...

A log of wood of mass 120 Kg floats in water. The weight that can be put on the raft to make it just sink, should be (density of wood `= 600 Kg//m`)

A

`80Kg`

B

`50Kg`

C

`60 Kg`

D

`30Kg`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of how much weight can be added to a floating log of wood to make it just sink, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Given Data:** - Mass of the log of wood, \( m_{\text{wood}} = 120 \, \text{kg} \) - Density of the wood, \( \rho_{\text{wood}} = 600 \, \text{kg/m}^3 \) 2. **Calculate the Volume of the Log:** - The volume \( V \) of the log can be calculated using the formula: \[ V = \frac{m_{\text{wood}}}{\rho_{\text{wood}}} \] - Substituting the values: \[ V = \frac{120 \, \text{kg}}{600 \, \text{kg/m}^3} = 0.2 \, \text{m}^3 \] 3. **Determine the Weight of the Log:** - The weight \( W_{\text{wood}} \) of the log is given by: \[ W_{\text{wood}} = m_{\text{wood}} \cdot g \] - Where \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \)). However, we can keep it in terms of mass since we will compare forces later. 4. **Calculate the Buoyant Force:** - The buoyant force \( F_b \) acting on the log when it is floating is equal to the weight of the water displaced by the volume of the log: \[ F_b = \rho_{\text{water}} \cdot V \cdot g \] - The density of water \( \rho_{\text{water}} = 1000 \, \text{kg/m}^3 \). Thus: \[ F_b = 1000 \, \text{kg/m}^3 \cdot 0.2 \, \text{m}^3 \cdot g = 200 \, \text{kg} \cdot g \] 5. **Set Up the Equilibrium Condition:** - For the log to just sink, the total weight (weight of the log plus the additional weight \( m \)) must equal the buoyant force: \[ W_{\text{wood}} + W_{\text{additional}} = F_b \] - In terms of mass: \[ 120 \, \text{kg} + m = 200 \, \text{kg} \] 6. **Solve for the Additional Mass \( m \):** - Rearranging the equation gives: \[ m = 200 \, \text{kg} - 120 \, \text{kg} = 80 \, \text{kg} \] 7. **Conclusion:** - The weight that can be put on the log to make it just sink is \( 80 \, \text{kg} \). ### Final Answer: The weight that can be added to the log to make it just sink is **80 kg**. ---
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