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Mass action ratio or reaction quotient Q...

Mass action ratio or reaction quotient Q for a reaction can be calculated using the law of mass actionl,
`A(g)+B(g)hArrC(g)+D(g)`
`Q=([C][D])/([A][B])`
The value of Q decides whether the reaction is at equilibrium or not.
At equilibrium, Q=K
For non-equilibrium process `QneK`
When `QgtK`, reaction will be favoured in backward direction and when `QltK`, it will be favoured in forward direction. In a reaction mixture containing `H_(2),N_(2)` and `NH_(3)` at partial pressure of 2 atm, 1 atm and 3 atm respectively, the value of `K_(p)` at 725 K is `4.28xx10^(-5)` `"atm"^(-2)`. In which direction the net reaction will go ?
`N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g)`

A

Forward

B

Backward

C

No net reaction

D

Direction cannot be predicated

Text Solution

Verified by Experts

The correct Answer is:
B
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