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According to Le Chatelier's principle, o...

According to Le Chatelier's principle, on applying any external force to desturb equilibrium, the reaction moves in that direction in which effect of exteranal force is minimised as far as possible. A container whose volume is V contains an equilibrium mixture that contains 2 moles each of `PCl_(5)`, `PCl_(3)` and `Cl_(2)`n (all gases). The pressure is 3atm and temperature is T. A certain amount of `Cl_(2)(g)` is now introduced keeping the pressure and temperature constant untill the equilbrium volume changes to 2 V.
`PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g)`. The equilibrium constant K of the reaction :

A

1

B

2

C

3

D

4

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The correct Answer is:
A
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According to Le Chatelier's principle, on applying any external force to desturb equilibrium, the reaction moves in that direction in which effect of exteranal force is minimised as far as possible. A container whose volume is V contains an equilibrium mixture that contains 2 moles each of PCl_(5) , PCl_(3) and Cl_(2) n (all gases). The pressure is 3atm and temperature is T. A certain amount of Cl_(2)(g) is now introduced keeping the pressure and temperature constant untill the equilbrium volume changes to 2 V. PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g) . The moles Cl_(2) that was added is :

For the reaction, PCl_(5)(g)to PCl_(3)(g)+Cl_(2)(g)

A container of volume V L contains an equilibrium mixture that consists of 2 mol each of gaseous PCl_(5), Pcl_(3) and Cl_(2) at 3 atm T K . Some Cl_(2) is added unitl the volume is double keeping P and T constant. Calculate moles of Cl_(2) added and K_(p) for PCl_(5) rarr PCl_(3)+Cl_(2)

For the reaction, PCl_(3)(g)+Cl_(2)(g) hArr PCl_(5)(g) , the position of equilibrium can be shifted to the right by:

n mole of PCl_(3) and n mole of Cl_(2) are allowed to react at constant temperature T to have a total equilibrium pressure P , as : PCl_(3)(g)+Cl_(2)(g) hArr PCl_(5)(g) If y mole of PCl_(5) are formed at equilibrium , find K_(p) for the given reaction .