One end of a metal rod is dipped in boiling water and the other is dipped in melting ice.

One end of a cylindrical rod is kept in steam chamber and the other end in melting Ice. Now 0.5 gm of ice melts in 1 sec. If the rod is replaced by another rod of same length, half the diameter and double the conductivity of the first rod, then rate of melting of ice will be

One end of a cylindrical rod is kept in steam chamber and the other end in melting Ice. Now 0.5gm of ice melts in 1sec if the rod is replaced by another rod of same length half the diameter then rate of melting of ice will be (in gm/sec) .

A metal rod 25 cm long and 10sq cm in cross section has it's one end placed in boiling water and the other end in melting ice. Calculate the mass of ice method per minute if K for metal is 378 W/mk. Latent heat of fusion of ice - 80 K cal/gm . J = 4200 j/Kcal.

One end of a uniform rod of length 1m is placed in boilling water while its other end is placed in boiling water while its other end is placed in melting ice A point P on the rod is maintained at a constant temperature of 800^(@)C mass of stam produced per second is equal to the mass of ice melted per second. is equal to mass of ice melted per second If specific latent heat of steam is 7 times the specific latent heat of ice, then the distance of P from the steam chamber is n//18 m Find the value of n ? .

One end of a uniform rod of length 10m is placed in boiling water while its other end is placed in melting ice. A point P on the rod is maintained at a constant temperature of 450^@C . The mass of steam produced per second is equal to the mass of ice melted per second. If specific latent heat of steam is 7 times the specific latent heat of ice, the distance of P from the steam chamber must be___________(in m)