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What is the ratio of the de Broglie wave...

What is the ratio of the de Broglie wavelength for electrons accelerated through 50 volts and 200 volts?

A

`3 :10`

B

`10:3`

C

`1:2`

D

`2:1`

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • The de Broglie wavelength lamda of an electron accelerated through a potential V in volts is

    A
    `(1.227)/(sqrt(V))nm`
    B
    `(0.1227)/(sqrt(V))nm`
    C
    `(0.01227)/(sqrt(V))nm`
    D
    `(12.27)/(sqrt(V))nm`

  • The ratio of de-Broglie wavelength associated with two electrons accelerated through 25V and 36V is

    A
    `25//36`
    B
    `36//25`
    C
    `5//6`
    D
    `6//5`

  • What will be the radio of de - broglie wave lenth of e^(-) accelerated with 400 volt and 100 volt :-

    A
    `1:2`
    B
    `2:1`
    C
    `3:10`
    D
    `10:3`

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    State de-Broglie relation for wavelength of matter waves. Show that the de-Broglie wavelength of electrons accelerated through a potential of V volt can be expressed as : lambda = h/sqrt(2meV)

    Find the ratio of de-Broglie wavelengths associated with two electrons accelerated through 25V and 36V.

    Show that the de-Broglie's wavelength of electrons accelerated through a potential V volts can be expressed as lamda=(h)/(sqrt(2meV)) . What is the de-Broglie wavelength of a 2 kg object moving with a speed of 1 ms^(-1) ?

    The ratio of de broglie wavelength of electron accelerated through potentials V_(1) and V_(2) is 1:2 the ratio of potentials V_(1) : V_(2) is

    Wavelength of an electron accelerated through a potential difference of 1 volt is

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