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de Broglie wavelength of an electron aft...

de Broglie wavelength of an electron after being accelerated by a potential difference of V volt from rest is :

A

`lambda = (12.3)/(sqrth) "Å"`

B

`lambda = (12.3)/(sqrtV) "Å"`

C

`lambda = (12.3)/(sqrtE) "Å"`

D

`lambda = (12.3)/(sqrtm) "Å"`

Text Solution

Verified by Experts

The correct Answer is:
B
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