An electron in a hydrogen like atom makes transition from a state in which itd de Broglie wavelength is `lambda_(1)` to a state where its de Broglie wavelength is `lambda_(2)` then wavelength of photon (`lambda`) generated will be :

Options

A. `lambda = lambda_(1) - lambda_(2)`
B. `lambda= (4mc)/(h) {(lambda_(1)^(2) lambda_(2)^(2))/(lambda_(1)^(2) - lambda_(2)^(2))}`
C. `lambda = sqrt((lambda_(1)^(2) lambda_(2)^(2))/(lambda_(1)^(2)- lambda_(2)^(2)))`
D. `lambda= (2mc)/(h) {(lambda_(1)^(2) lambda_(2)^(2))/(lambda_(1)^(2) - lambda_(2)^(2))}`

Answer

D