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The de Broglie wavelength of an electron...

The de Broglie wavelength of an electron moving in a circular orbit is `lambda` . The minimum radius of orbit is :

A

`(lambda)/(4)`

B

`(lambda)/(2pi)`

C

`(lambda)/(4 pi)`

D

`(lambda)/(3 pi)`

Text Solution

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The correct Answer is:
B
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