Home
Class 11
CHEMISTRY
A photon of energy 12 eV can break three...

A photon of energy `12 eV` can break three molecules of `A_2` into atoms which has bond dissociation energy of `4 eV//"molecule"`.
Total energy is conserved and interaction is always one to one between photon and molecule.

Text Solution

Verified by Experts

The correct Answer is:
d
Promotional Banner

Topper's Solved these Questions

  • ATOMIC STRUCTURE

    GRB PUBLICATION|Exercise Multiple Objective Type|49 Videos
  • ATOMIC STRUCTURE

    GRB PUBLICATION|Exercise Comprehesion Type|38 Videos
  • ATOMIC STRUCTURE

    GRB PUBLICATION|Exercise Schrodinger Wave equation|24 Videos
  • CHEMICAL EQUILIBRIUM

    GRB PUBLICATION|Exercise D.Le Chateliera principle|16 Videos

Similar Questions

Explore conceptually related problems

How is bond order related to bond length and bond dissociation energy of a molecule ?

Which of the following pairs of molecules have the almost identical bond dissociation energy?

A photon of energy 10.5eV is allowed to interact with a hydrogen atom in its ground state. Then :

A photon beam of energy 12.1eV is incident on a hydrogen atom. The orbit to which electron of H-atom be excited is

A hydrogen atom is in a state of ionization energy 0.85 eV. If it makes a transition to the ground state, what is the energy of the emitted photon.

A photon of energy 12.09 eV is absorbed by an electron in ground state of a hydrogen atoms. What will be the energy level of electron ? The energy of electron in the ground state of hydrogen atom is -13.6 eV

A photon of energy 12.09 eV is completely absorbed by a hydrogen atom initially in the ground state. The quantum number of excited state is