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Radiatonal wavelength (lambda)=124nm fal...

Radiatonal wavelength `(lambda)=124nm` falls on a metallic surface then the kinetic energy of the ejected photo electron(s) can be : [Given that threshold wavelength `(lambda_(0))=248nm]`

A

1 eV

B

2 eV

C

3 eV

D

5 eV

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The correct Answer is:
a b c d
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