Home
Class 11
CHEMISTRY
An unknown gas behaves ideally at 540 K ...

An unknown gas behaves ideally at 540 K in low pressure region, then calculate the temperature (in K) below which it can be liquefied by applying pressure.

Text Solution

Verified by Experts

The correct Answer is:
160
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    GRB PUBLICATION|Exercise D.Le Chateliera principle|16 Videos

  • ISOMERISM

    GRB PUBLICATION|Exercise SUBJECTIVE TYPE|67 Videos

Similar Questions

Explore conceptually related problems

The essential conditions for liquefaction of gases were discovered by Andrews in 1869 as a result of his study of pressure-volume-temperature relationship for CO_(2) . If was found that above a certain temperature, it was impossible to liquefy a gas whatever the pressure was applied. The temperature below which the gas can be liquefied by the application of pressure alone is called critical temperature (T_(c)) . The pressure required to liquefy a gas at this temperature is called the critical pressure (P_(c)) . The volume occupied by one mole of the substance at the critical temperature and pressure is called critcal volume. Critical constants are related with van der Waals' constant as follows: V_(c) = 3b, P_(c) = (a)/(27b^(2)), T_(c) = (8a)/(27 Rb) {:("Gases",A,B,C,D,),(P_(c) (atm),2.2,14,35,45,),(T_(c) (K),5.1,33,127,140,):} Which of the above gases cannot be liquefied at 100 K and 50 atm ?

The essential conditions for liquefaction of gases were discovered by Andrews in 1869 as a result of his study of pressure-volume-temperature relationship for CO_(2) . If was found that above a certain temperature, it was impossible to liquefy a gas whatever the pressure was applied. The temperature below which the gas can be liquefied by the application of pressure alone is called critical temperature (T_(c)) . The pressure required to liquefy a gas at this temperature is called the critical pressure (P_(c)) . The volume occupied by one mole of the substance at the critical temperature and pressure is called critcal volume. Critical constants are related with van der Waals' constant as follows: V_(c) = 3b, P_(c) = (a)/(27b^(2)), T_(c) = (8a)/(27 Rb) Gas A and can be liquefied at room temperature by applying pressure but gas B cannot. This reflects:

The essential conditions for liquefaction of gases were discovered by Andrews in 1869 as a result of his study of pressure-volume-temperature relationship for CO_(2) . If was found that above a certain temperature, it was impossible to liquefy a gas whatever the pressure was applied. The temperature below which the gas can be liquefied by the application of pressure alone is called critical temperature (T_(c)) . The pressure required to liquefy a gas at this temperature is called the critical pressure (P_(c)) . The volume occupied by one mole of the substance at the critical temperature and pressure is called critcal volume. Critical constants are related with van der Waals' constant as follows: V_(c) = 3b, P_(c) = (a)/(27b^(2)), T_(c) = (8a)/(27 Rb) The pressure required to liquefy a gas at the critical temperature is called :

The temperature above which the gas cannot be liquefied by any amount of pressure is called…………………...

CO_(2) gas can be liquefied under pressure between

A gas can be liquefied by pressure alone when its temperature

For a real gas, behaving ideally, the pressure may be:

GRB PUBLICATION-GASEOUS STATE-Exercise
  1. A thin glass tube (uniform cross-section) is filled with He and SO(2) ...

    Text Solution

    |

  2. If above tube is held vertical with open end upward then find the leng...

    Text Solution

    |

  3. An unknown gas behaves ideally at 540 K in low pressure region, then c...

    Text Solution

    |

  4. A flask has 10 molecules out of which four molecules are moving at 7 m...

    Text Solution

    |

  5. Two flask of equal volume are connected by a narrow tube (of negligibl...

    Text Solution

    |

  6. The van der Waal's constants for a gas are a=1.92 atm L^(2) "mol"^(-2)...

    Text Solution

    |

  7. Calculate the mole present of N(2) gas in a mixture of N(2) and O(2) i...

    Text Solution

    |

  8. Some gas is present in J-shaped tube and in this case level of mecury ...

    Text Solution

    |

  9. The density of a mixturee of O(2) and N(2) gases at 1 atm and 273 K is...

    Text Solution

    |

  10. One litre gaseous mixture is effused in 4.5 minutes and 30 seconds whi...

    Text Solution

    |

  11. Gas A taken in a closed rigid container is allowed to decompose partia...

    Text Solution

    |

  12. For a real gas critical pressure is 75 atm and van der Waal's constant...

    Text Solution

    |

  13. 2 moles of NO(g) and 16 gm of O(2)(g) were mixed in a 6.25 litre vesse...

    Text Solution

    |

  14. If the mean free path is 10 cm at one bar pressure, then, its value in...

    Text Solution

    |

  15. Average translational kinetic energy of an ideal gas molecule at 27^(@...

    Text Solution

    |

  16. H(2) and O(2) are kept in mass ratio 1:8 respectively at 6 atm. If sma...

    Text Solution

    |

  17. Calulate the mole fraction of N(2) gas in a mixture of N(2) and O(2). ...

    Text Solution

    |

  18. If at 200 K and 500 atm, density of CH(4) is 0.246 g//mL then its comp...

    Text Solution

    |

  19. Density of ideal gas at 2.46 atm and 300 K is 0.8 g//L Hence g-molar m...

    Text Solution

    |

  20. At 300 K two gases are filled in two equal sized containers as given ...

    Text Solution

    |