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3.65gm equimole mixture of NaOH and Na(2...

3.65gm equimole mixture of `NaOH` and `Na_(2)CO_(3)` is titrated against `0.1M HCl` using phenolphathalein as an indicator, `V_(1)mL` of acid was required to reach end point. In another experiment `3.65gm` of same mixture is titrated against 0.2M HCl using methyl orange as an indicator, `V_(2)mL` of acid was required to reach end point. `V_(1)+V_(2)` is :

A

875mL

B

750mL

C

500mL

D

1000mL

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The correct Answer is:
a
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